Optimal. Leaf size=191 \[ -\frac {3 a}{8 \left (1-a^2 x^2\right )}+\frac {3 a^2 x \tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^2-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}+a \tanh ^{-1}(a x)^3-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^4+3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac {2}{1+a x}\right )-3 a \tanh ^{-1}(a x) \text {PolyLog}\left (2,-1+\frac {2}{1+a x}\right )-\frac {3}{2} a \text {PolyLog}\left (3,-1+\frac {2}{1+a x}\right ) \]
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Rubi [A]
time = 0.31, antiderivative size = 191, normalized size of antiderivative = 1.00, number of steps
used = 12, number of rules used = 11, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6177, 6129,
6037, 6135, 6079, 6095, 6203, 6745, 6103, 6141, 267} \begin {gather*} -\frac {3 a}{8 \left (1-a^2 x^2\right )}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}+\frac {3 a^2 x \tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )}-\frac {3}{2} a \text {Li}_3\left (\frac {2}{a x+1}-1\right )-3 a \text {Li}_2\left (\frac {2}{a x+1}-1\right ) \tanh ^{-1}(a x)+\frac {3}{8} a \tanh ^{-1}(a x)^4+a \tanh ^{-1}(a x)^3-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {3}{8} a \tanh ^{-1}(a x)^2+3 a \log \left (2-\frac {2}{a x+1}\right ) \tanh ^{-1}(a x)^2 \end {gather*}
Antiderivative was successfully verified.
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Rule 267
Rule 6037
Rule 6079
Rule 6095
Rule 6103
Rule 6129
Rule 6135
Rule 6141
Rule 6177
Rule 6203
Rule 6745
Rubi steps
\begin {align*} \int \frac {\tanh ^{-1}(a x)^3}{x^2 \left (1-a^2 x^2\right )^2} \, dx &=a^2 \int \frac {\tanh ^{-1}(a x)^3}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac {\tanh ^{-1}(a x)^3}{x^2 \left (1-a^2 x^2\right )} \, dx\\ &=\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {1}{8} a \tanh ^{-1}(a x)^4+a^2 \int \frac {\tanh ^{-1}(a x)^3}{1-a^2 x^2} \, dx-\frac {1}{2} \left (3 a^3\right ) \int \frac {x \tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac {\tanh ^{-1}(a x)^3}{x^2} \, dx\\ &=-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^4+(3 a) \int \frac {\tanh ^{-1}(a x)^2}{x \left (1-a^2 x^2\right )} \, dx+\frac {1}{2} \left (3 a^2\right ) \int \frac {\tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx\\ &=\frac {3 a^2 x \tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^2-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}+a \tanh ^{-1}(a x)^3-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^4+(3 a) \int \frac {\tanh ^{-1}(a x)^2}{x (1+a x)} \, dx-\frac {1}{4} \left (3 a^3\right ) \int \frac {x}{\left (1-a^2 x^2\right )^2} \, dx\\ &=-\frac {3 a}{8 \left (1-a^2 x^2\right )}+\frac {3 a^2 x \tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^2-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}+a \tanh ^{-1}(a x)^3-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^4+3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac {2}{1+a x}\right )-\left (6 a^2\right ) \int \frac {\tanh ^{-1}(a x) \log \left (2-\frac {2}{1+a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac {3 a}{8 \left (1-a^2 x^2\right )}+\frac {3 a^2 x \tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^2-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}+a \tanh ^{-1}(a x)^3-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^4+3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac {2}{1+a x}\right )-3 a \tanh ^{-1}(a x) \text {Li}_2\left (-1+\frac {2}{1+a x}\right )+\left (3 a^2\right ) \int \frac {\text {Li}_2\left (-1+\frac {2}{1+a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac {3 a}{8 \left (1-a^2 x^2\right )}+\frac {3 a^2 x \tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^2-\frac {3 a \tanh ^{-1}(a x)^2}{4 \left (1-a^2 x^2\right )}+a \tanh ^{-1}(a x)^3-\frac {\tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{2 \left (1-a^2 x^2\right )}+\frac {3}{8} a \tanh ^{-1}(a x)^4+3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac {2}{1+a x}\right )-3 a \tanh ^{-1}(a x) \text {Li}_2\left (-1+\frac {2}{1+a x}\right )-\frac {3}{2} a \text {Li}_3\left (-1+\frac {2}{1+a x}\right )\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 0.22, size = 144, normalized size = 0.75 \begin {gather*} \frac {1}{16} a \left (2 i \pi ^3-16 \tanh ^{-1}(a x)^3-\frac {16 \tanh ^{-1}(a x)^3}{a x}+6 \tanh ^{-1}(a x)^4-3 \cosh \left (2 \tanh ^{-1}(a x)\right )-6 \tanh ^{-1}(a x)^2 \cosh \left (2 \tanh ^{-1}(a x)\right )+48 \tanh ^{-1}(a x)^2 \log \left (1-e^{2 \tanh ^{-1}(a x)}\right )+48 \tanh ^{-1}(a x) \text {PolyLog}\left (2,e^{2 \tanh ^{-1}(a x)}\right )-24 \text {PolyLog}\left (3,e^{2 \tanh ^{-1}(a x)}\right )+6 \tanh ^{-1}(a x) \sinh \left (2 \tanh ^{-1}(a x)\right )+4 \tanh ^{-1}(a x)^3 \sinh \left (2 \tanh ^{-1}(a x)\right )\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 138.15, size = 271, normalized size = 1.42
method | result | size |
derivativedivides | \(a \left (\frac {3 \arctanh \left (a x \right )^{4}}{8}-\frac {\left (a x +1\right ) \left (4 \arctanh \left (a x \right )^{3}-6 \arctanh \left (a x \right )^{2}+6 \arctanh \left (a x \right )-3\right )}{32 \left (a x -1\right )}+\frac {\left (4 \arctanh \left (a x \right )^{3}+6 \arctanh \left (a x \right )^{2}+6 \arctanh \left (a x \right )+3\right ) \left (a x -1\right )}{32 a x +32}+\frac {\arctanh \left (a x \right )^{3} \left (a x -1\right )}{a x}-2 \arctanh \left (a x \right )^{3}+3 \arctanh \left (a x \right )^{2} \ln \left (1+\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+6 \arctanh \left (a x \right ) \polylog \left (2, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-6 \polylog \left (3, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+3 \arctanh \left (a x \right )^{2} \ln \left (1-\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+6 \arctanh \left (a x \right ) \polylog \left (2, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-6 \polylog \left (3, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )\right )\) | \(271\) |
default | \(a \left (\frac {3 \arctanh \left (a x \right )^{4}}{8}-\frac {\left (a x +1\right ) \left (4 \arctanh \left (a x \right )^{3}-6 \arctanh \left (a x \right )^{2}+6 \arctanh \left (a x \right )-3\right )}{32 \left (a x -1\right )}+\frac {\left (4 \arctanh \left (a x \right )^{3}+6 \arctanh \left (a x \right )^{2}+6 \arctanh \left (a x \right )+3\right ) \left (a x -1\right )}{32 a x +32}+\frac {\arctanh \left (a x \right )^{3} \left (a x -1\right )}{a x}-2 \arctanh \left (a x \right )^{3}+3 \arctanh \left (a x \right )^{2} \ln \left (1+\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+6 \arctanh \left (a x \right ) \polylog \left (2, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-6 \polylog \left (3, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+3 \arctanh \left (a x \right )^{2} \ln \left (1-\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+6 \arctanh \left (a x \right ) \polylog \left (2, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-6 \polylog \left (3, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )\right )\) | \(271\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\operatorname {atanh}^{3}{\left (a x \right )}}{x^{2} \left (a x - 1\right )^{2} \left (a x + 1\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\mathrm {atanh}\left (a\,x\right )}^3}{x^2\,{\left (a^2\,x^2-1\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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